How to extract the hostname portion of a URL in JavaScript

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Is there a really easy way to start from a full URL:

document.location.href = "http://aaa.bbb.ccc.com/asdf/asdf/sadf.aspx?blah"

And extract just the host part:

aaa.bbb.ccc.com

There's gotta be a JavaScript function that does this reliably, but I can't find it.

This Question Has 11 Answeres | Orginal Question | Dustin Getz

I would like to specify something. If someone want to get the whole url with path like I need, can use:

var fullUrl = window.location.protocol + "//" + window.location.hostname + window.location.pathname;

You could concatenate the location protocol and the host:

var root = location.protocol + '//' + location.host;

For a url, let say 'http://stackoverflow.com/questions', it will return 'http://stackoverflow.com'

There are two ways. The first is a variant of another answer here, but this one accounts for non-default ports:

function getRootUrl() {
  var defaultPorts = {"http:":80,"https:":443};

  return window.location.protocol + "//" + window.location.hostname
   + (((window.location.port)
    && (window.location.port != defaultPorts[window.location.protocol]))
    ? (":"+window.location.port) : "");
}

But I prefer this simpler method (which works with any URI string):

function getRootUrl(url) {
  return url.toString().replace(/^(.*\/\/[^\/?#]*).*$/,"$1");
}

There is another hack I use and never saw in any StackOverflow response : using "src" attribute of an image will yield the complete base path of your site. For instance :

var dummy = new Image;
dummy.src = '$';                  // using '' will fail on some browsers
var root = dummy.src.slice(0,-1); // remove trailing '$'

On an URL like http://domain.com/somesite/index.html,root will be set to http://domain.com/somesite/. This also works for localhost or any valid base URL.

Note that this will cause a failed HTTP request on the $ dummy image. You can use an existing image instead to avoid this, with only slight code changes.

Another variant uses a dummy link, with no side effect on HTTP requests :

var dummy = document.createElement ('a');
dummy.href = '';
var root = dummy.href;

I did not test it on every browser, though.

Use document.location object and its host or hostname properties.

alert(document.location.hostname); // alerts "stackoverflow.com"

The accepted answer didn't work for me since wanted to be able to work with any arbitary url's, not just the current page URL.

Take a look at the URL object:

var url = new URL("http://aaa.bbb.ccc.com/asdf/asdf/sadf.aspx?blah");
url.protocol;  // "http:"
url.hostname;  // "aaa.bbb.ccc.com"
url.pathname;  // "/asdf/asdf/sadf.aspx"
url.search;    // "?blah"

suppose that you have a page with this address: http://sub.domain.com/virtualPath/page.htm. use the following in page code to achive those results:

  • window.location.host : you'll get sub.domain.com:8080 or sub.domain.com:80
  • window.location.hostname : you'll get sub.domain.com
  • window.location.protocol : you'll get http:
  • window.location.port : you'll get 8080 or 80
  • window.location.pathname : you'll get /virtualPath
  • window.location.origin : you'll get http://sub.domain.com *****

Update: about the .origin

***** As the ref states, browser compatibility for window.location.origin is not clear. I've checked it in chrome and it returned http://sub.domain.com:port if the port is anything but 80, and http://sub.domain.com if the port is 80.

Special thanks to @torazaburo for mentioning that to me.

Check this:

alert(window.location.hostname);

this will return host name as www.domain.com

and:

window.location.host

will return domain name with port like www.example.com:80

For complete reference check Mozilla developer site.

Try

document.location.host

or

document.location.hostname

use

window.location.origin

and for: "http://aaa.bbb.ccc.ddd.com/sadf.aspx?blah"

you will get: http://aaa.bbb.ccc.ddd.com/

As Martin said, the other answers won't work with arbitrary urls. The new URL object will work but is still experimental and not compatible with all browsers.

For a more reliable and cross browser solution, you can use this component I built to parse an arbitrary url into properties similar to those found in the above URL object.

For example:

var urlObject = parseUrl('http://aaa.bbb.ccc.com/asdf/asdf/sadf.aspx?blah');
var newUrl = urlObject.hostname;

newUrl will now contain:

aaa.bbb.ccc.com

You can import the component to use parseUrl()


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